24h^2-8h-42=0

Solution for 24h^2-8h-42=0 equation:

24h^2-8h-42=0

a = 24; b = -8; c = -42;
Δ = b2-4ac
Δ = -82-4·24·(-42)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-64}{2*24}=\frac{-56}{48}
=-1+1/6
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+64}{2*24}=\frac{72}{48}
=1+1/2
$